6(2x+1)=3x+33

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Solution for 6(2x+1)=3x+33 equation: 



6(2x+1)=3x+33

We move all terms to the left:

6(2x+1)-(3x+33)=0

We multiply parentheses

12x-(3x+33)+6=0

We get rid of parentheses

12x-3x-33+6=0

We add all the numbers together, and all the variables

9x-27=0

We move all terms containing x to the left, all other terms to the right

9x=27

x=27/9

x=3

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