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6(2x+1)=4(x+7)
We move all terms to the left:
6(2x+1)-(4(x+7))=0
We multiply parentheses
12x-(4(x+7))+6=0
We calculate terms in parentheses: -(4(x+7)), so:We get rid of parentheses
4(x+7)
We multiply parentheses
4x+28
Back to the equation:
-(4x+28)
12x-4x-28+6=0
We add all the numbers together, and all the variables
8x-22=0
We move all terms containing x to the left, all other terms to the right
8x=22
x=22/8
x=2+3/4
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