6(2x+1)=4x+8(x+4)

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Solution for 6(2x+1)=4x+8(x+4) equation: 



6(2x+1)=4x+8(x+4)

We move all terms to the left:

6(2x+1)-(4x+8(x+4))=0

We multiply parentheses

12x-(4x+8(x+4))+6=0



We calculate terms in parentheses: -(4x+8(x+4)), so:

4x+8(x+4)

We multiply parentheses

4x+8x+32

We add all the numbers together, and all the variables

12x+32

Back to the equation:

-(12x+32)



We get rid of parentheses

12x-12x-32+6=0

We add all the numbers together, and all the variables

-26!=0

There is no solution for this equation

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