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6(2x+1)=6+12x
We move all terms to the left:
6(2x+1)-(6+12x)=0
We add all the numbers together, and all the variables
6(2x+1)-(12x+6)=0
We multiply parentheses
12x-(12x+6)+6=0
We get rid of parentheses
12x-12x-6+6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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