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6(2x+2)=3(x-6)
We move all terms to the left:
6(2x+2)-(3(x-6))=0
We multiply parentheses
12x-(3(x-6))+12=0
We calculate terms in parentheses: -(3(x-6)), so:We get rid of parentheses
3(x-6)
We multiply parentheses
3x-18
Back to the equation:
-(3x-18)
12x-3x+18+12=0
We add all the numbers together, and all the variables
9x+30=0
We move all terms containing x to the left, all other terms to the right
9x=-30
x=-30/9
x=-3+1/3
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