6(2x+3)+8=8(2+x)-1x

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Solution for 6(2x+3)+8=8(2+x)-1x equation: 



6(2x+3)+8=8(2+x)-1x

We move all terms to the left:

6(2x+3)+8-(8(2+x)-1x)=0

We add all the numbers together, and all the variables

6(2x+3)-(8(x+2)-1x)+8=0

We multiply parentheses

12x-(8(x+2)-1x)+18+8=0



We calculate terms in parentheses: -(8(x+2)-1x), so:

8(x+2)-1x

We add all the numbers together, and all the variables

-1x+8(x+2)

We multiply parentheses

-1x+8x+16

We add all the numbers together, and all the variables

7x+16

Back to the equation:

-(7x+16)



We add all the numbers together, and all the variables

12x-(7x+16)+26=0

We get rid of parentheses

12x-7x-16+26=0

We add all the numbers together, and all the variables

5x+10=0

We move all terms containing x to the left, all other terms to the right

5x=-10

x=-10/5

x=-2

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