6(2x+3)=10x+2x+18

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Solution for 6(2x+3)=10x+2x+18 equation: 



6(2x+3)=10x+2x+18

We move all terms to the left:

6(2x+3)-(10x+2x+18)=0

We add all the numbers together, and all the variables

6(2x+3)-(12x+18)=0

We multiply parentheses

12x-(12x+18)+18=0

We get rid of parentheses

12x-12x-18+18=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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