6(2x+3)=2(4x-5)

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Solution for 6(2x+3)=2(4x-5) equation: 



6(2x+3)=2(4x-5)

We move all terms to the left:

6(2x+3)-(2(4x-5))=0

We multiply parentheses

12x-(2(4x-5))+18=0



We calculate terms in parentheses: -(2(4x-5)), so:

2(4x-5)

We multiply parentheses

8x-10

Back to the equation:

-(8x-10)



We get rid of parentheses

12x-8x+10+18=0

We add all the numbers together, and all the variables

4x+28=0

We move all terms containing x to the left, all other terms to the right

4x=-28

x=-28/4

x=-7

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