6(2x+3)=3(x-5)

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Solution for 6(2x+3)=3(x-5) equation: 



6(2x+3)=3(x-5)

We move all terms to the left:

6(2x+3)-(3(x-5))=0

We multiply parentheses

12x-(3(x-5))+18=0



We calculate terms in parentheses: -(3(x-5)), so:

3(x-5)

We multiply parentheses

3x-15

Back to the equation:

-(3x-15)



We get rid of parentheses

12x-3x+15+18=0

We add all the numbers together, and all the variables

9x+33=0

We move all terms containing x to the left, all other terms to the right

9x=-33

x=-33/9

x=-3+2/3

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