6(2x+3)=4(4x-2)

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Solution for 6(2x+3)=4(4x-2) equation: 



6(2x+3)=4(4x-2)

We move all terms to the left:

6(2x+3)-(4(4x-2))=0

We multiply parentheses

12x-(4(4x-2))+18=0



We calculate terms in parentheses: -(4(4x-2)), so:

4(4x-2)

We multiply parentheses

16x-8

Back to the equation:

-(16x-8)



We get rid of parentheses

12x-16x+8+18=0

We add all the numbers together, and all the variables

-4x+26=0

We move all terms containing x to the left, all other terms to the right

-4x=-26

x=-26/-4

x=6+1/2

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