6(2x+3)=7x+33

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Solution for 6(2x+3)=7x+33 equation: 



6(2x+3)=7x+33

We move all terms to the left:

6(2x+3)-(7x+33)=0

We multiply parentheses

12x-(7x+33)+18=0

We get rid of parentheses

12x-7x-33+18=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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