6(2x+3)=9(1x-2)

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Solution for 6(2x+3)=9(1x-2) equation:



6(2x+3)=9(1x-2)
We move all terms to the left:
6(2x+3)-(9(1x-2))=0
We add all the numbers together, and all the variables
6(2x+3)-(9(x-2))=0
We multiply parentheses
12x-(9(x-2))+18=0
We calculate terms in parentheses: -(9(x-2)), so:
9(x-2)
We multiply parentheses
9x-18
Back to the equation:
-(9x-18)
We get rid of parentheses
12x-9x+18+18=0
We add all the numbers together, and all the variables
3x+36=0
We move all terms containing x to the left, all other terms to the right
3x=-36
x=-36/3
x=-12

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