6(2x+4)1/2(8+3x)=-20

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Solution for 6(2x+4)1/2(8+3x)=-20 equation: 



6(2x+4)1/2(8+3x)=-20

We move all terms to the left:

6(2x+4)1/2(8+3x)-(-20)=0



Domain of the equation: 2(8+3x)!=0

x∈R



We add all the numbers together, and all the variables

6(2x+4)1/2(3x+8)-(-20)=0

We add all the numbers together, and all the variables

6(2x+4)1/2(3x+8)+20=0

We multiply all the terms by the denominator


6(2x+4)1+20*2(3x+8)=0

We multiply parentheses

12x+20*2(3x+8)+24=0

Wy multiply elements

12x+40x(3+24=0

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