6(2x+4)=10+3(4-1)

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Solution for 6(2x+4)=10+3(4-1) equation: 



6(2x+4)=10+3(4-1)

We move all terms to the left:

6(2x+4)-(10+3(4-1))=0

We add all the numbers together, and all the variables

6(2x+4)-(10+33)=0

We add all the numbers together, and all the variables

6(2x+4)-43=0

We multiply parentheses

12x+24-43=0

We add all the numbers together, and all the variables

12x-19=0

We move all terms containing x to the left, all other terms to the right

12x=19

x=19/12

x=1+7/12

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