6(2x+5)+6(4x+3)+3=36x+51

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Solution for 6(2x+5)+6(4x+3)+3=36x+51 equation: 



6(2x+5)+6(4x+3)+3=36x+51

We move all terms to the left:

6(2x+5)+6(4x+3)+3-(36x+51)=0

We multiply parentheses

12x+24x-(36x+51)+30+18+3=0

We get rid of parentheses

12x+24x-36x-51+30+18+3=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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