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6(2x+5)=(x-7)
We move all terms to the left:
6(2x+5)-((x-7))=0
We multiply parentheses
12x-((x-7))+30=0
We calculate terms in parentheses: -((x-7)), so:We get rid of parentheses
(x-7)
We get rid of parentheses
x-7
Back to the equation:
-(x-7)
12x-x+7+30=0
We add all the numbers together, and all the variables
11x+37=0
We move all terms containing x to the left, all other terms to the right
11x=-37
x=-37/11
x=-3+4/11
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