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6(2x+5)=7x+5(x+6)
We move all terms to the left:
6(2x+5)-(7x+5(x+6))=0
We multiply parentheses
12x-(7x+5(x+6))+30=0
We calculate terms in parentheses: -(7x+5(x+6)), so:We get rid of parentheses
7x+5(x+6)
We multiply parentheses
7x+5x+30
We add all the numbers together, and all the variables
12x+30
Back to the equation:
-(12x+30)
12x-12x-30+30=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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