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6(2x+7)-12=3(3x-5)+6
We move all terms to the left:
6(2x+7)-12-(3(3x-5)+6)=0
We multiply parentheses
12x-(3(3x-5)+6)+42-12=0
We calculate terms in parentheses: -(3(3x-5)+6), so:We add all the numbers together, and all the variables
3(3x-5)+6
We multiply parentheses
9x-15+6
We add all the numbers together, and all the variables
9x-9
Back to the equation:
-(9x-9)
12x-(9x-9)+30=0
We get rid of parentheses
12x-9x+9+30=0
We add all the numbers together, and all the variables
3x+39=0
We move all terms containing x to the left, all other terms to the right
3x=-39
x=-39/3
x=-13
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