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6(2x+7)=3(x+5)
We move all terms to the left:
6(2x+7)-(3(x+5))=0
We multiply parentheses
12x-(3(x+5))+42=0
We calculate terms in parentheses: -(3(x+5)), so:We get rid of parentheses
3(x+5)
We multiply parentheses
3x+15
Back to the equation:
-(3x+15)
12x-3x-15+42=0
We add all the numbers together, and all the variables
9x+27=0
We move all terms containing x to the left, all other terms to the right
9x=-27
x=-27/9
x=-3
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