6(2x+8)=4+4(1+8x)

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Solution for 6(2x+8)=4+4(1+8x) equation:



6(2x+8)=4+4(1+8x)
We move all terms to the left:
6(2x+8)-(4+4(1+8x))=0
We add all the numbers together, and all the variables
6(2x+8)-(4+4(8x+1))=0
We multiply parentheses
12x-(4+4(8x+1))+48=0
We calculate terms in parentheses: -(4+4(8x+1)), so:
4+4(8x+1)
determiningTheFunctionDomain 4(8x+1)+4
We multiply parentheses
32x+4+4
We add all the numbers together, and all the variables
32x+8
Back to the equation:
-(32x+8)
We get rid of parentheses
12x-32x-8+48=0
We add all the numbers together, and all the variables
-20x+40=0
We move all terms containing x to the left, all other terms to the right
-20x=-40
x=-40/-20
x=+2

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