6(2x-1)+10=8(2x+3)

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Solution for 6(2x-1)+10=8(2x+3) equation: 



6(2x-1)+10=8(2x+3)

We move all terms to the left:

6(2x-1)+10-(8(2x+3))=0

We multiply parentheses

12x-(8(2x+3))-6+10=0



We calculate terms in parentheses: -(8(2x+3)), so:

8(2x+3)

We multiply parentheses

16x+24

Back to the equation:

-(16x+24)



We add all the numbers together, and all the variables

12x-(16x+24)+4=0

We get rid of parentheses

12x-16x-24+4=0

We add all the numbers together, and all the variables

-4x-20=0

We move all terms containing x to the left, all other terms to the right

-4x=20

x=20/-4

x=-5

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