6(2x-1)+10=8(2x+3)

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Solution for 6(2x-1)+10=8(2x+3) equation:



6(2x-1)+10=8(2x+3)
We move all terms to the left:
6(2x-1)+10-(8(2x+3))=0
We multiply parentheses
12x-(8(2x+3))-6+10=0
We calculate terms in parentheses: -(8(2x+3)), so:
8(2x+3)
We multiply parentheses
16x+24
Back to the equation:
-(16x+24)
We add all the numbers together, and all the variables
12x-(16x+24)+4=0
We get rid of parentheses
12x-16x-24+4=0
We add all the numbers together, and all the variables
-4x-20=0
We move all terms containing x to the left, all other terms to the right
-4x=20
x=20/-4
x=-5

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