6(2x-1)-(x-4)=-2(3x+2)

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Solution for 6(2x-1)-(x-4)=-2(3x+2) equation: 



6(2x-1)-(x-4)=-2(3x+2)

We move all terms to the left:

6(2x-1)-(x-4)-(-2(3x+2))=0

We multiply parentheses

12x-(x-4)-(-2(3x+2))-6=0

We get rid of parentheses

12x-x-(-2(3x+2))+4-6=0



We calculate terms in parentheses: -(-2(3x+2)), so:

-2(3x+2)

We multiply parentheses

-6x-4

Back to the equation:

-(-6x-4)



We add all the numbers together, and all the variables

11x-(-6x-4)-2=0

We get rid of parentheses

11x+6x+4-2=0

We add all the numbers together, and all the variables

17x+2=0

We move all terms containing x to the left, all other terms to the right

17x=-2

x=-2/17

x=-2/17

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