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6(2x-1)-12=2(x+10)
We move all terms to the left:
6(2x-1)-12-(2(x+10))=0
We multiply parentheses
12x-(2(x+10))-6-12=0
We calculate terms in parentheses: -(2(x+10)), so:We add all the numbers together, and all the variables
2(x+10)
We multiply parentheses
2x+20
Back to the equation:
-(2x+20)
12x-(2x+20)-18=0
We get rid of parentheses
12x-2x-20-18=0
We add all the numbers together, and all the variables
10x-38=0
We move all terms containing x to the left, all other terms to the right
10x=38
x=38/10
x=3+4/5
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