6(2x-1)-3(x+3)=2(3x-1)+6

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Solution for 6(2x-1)-3(x+3)=2(3x-1)+6 equation: 



6(2x-1)-3(x+3)=2(3x-1)+6

We move all terms to the left:

6(2x-1)-3(x+3)-(2(3x-1)+6)=0

We multiply parentheses

12x-3x-(2(3x-1)+6)-6-9=0



We calculate terms in parentheses: -(2(3x-1)+6), so:

2(3x-1)+6

We multiply parentheses

6x-2+6

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We add all the numbers together, and all the variables

9x-(6x+4)-15=0

We get rid of parentheses

9x-6x-4-15=0

We add all the numbers together, and all the variables

3x-19=0

We move all terms containing x to the left, all other terms to the right

3x=19

x=19/3

x=6+1/3

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