6(2x-1)-5(x-3)=2(x-2)

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Solution for 6(2x-1)-5(x-3)=2(x-2) equation: 



6(2x-1)-5(x-3)=2(x-2)

We move all terms to the left:

6(2x-1)-5(x-3)-(2(x-2))=0

We multiply parentheses

12x-5x-(2(x-2))-6+15=0



We calculate terms in parentheses: -(2(x-2)), so:

2(x-2)

We multiply parentheses

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

7x-(2x-4)+9=0

We get rid of parentheses

7x-2x+4+9=0

We add all the numbers together, and all the variables

5x+13=0

We move all terms containing x to the left, all other terms to the right

5x=-13

x=-13/5

x=-2+3/5

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