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6(2x-1)=2(5x-2)+1
We move all terms to the left:
6(2x-1)-(2(5x-2)+1)=0
We multiply parentheses
12x-(2(5x-2)+1)-6=0
We calculate terms in parentheses: -(2(5x-2)+1), so:We get rid of parentheses
2(5x-2)+1
We multiply parentheses
10x-4+1
We add all the numbers together, and all the variables
10x-3
Back to the equation:
-(10x-3)
12x-10x+3-6=0
We add all the numbers together, and all the variables
2x-3=0
We move all terms containing x to the left, all other terms to the right
2x=3
x=3/2
x=1+1/2
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