6(2x-1)=3(2x+4)-10

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Solution for 6(2x-1)=3(2x+4)-10 equation: 



6(2x-1)=3(2x+4)-10

We move all terms to the left:

6(2x-1)-(3(2x+4)-10)=0

We multiply parentheses

12x-(3(2x+4)-10)-6=0



We calculate terms in parentheses: -(3(2x+4)-10), so:

3(2x+4)-10

We multiply parentheses

6x+12-10

We add all the numbers together, and all the variables

6x+2

Back to the equation:

-(6x+2)



We get rid of parentheses

12x-6x-2-6=0

We add all the numbers together, and all the variables

6x-8=0

We move all terms containing x to the left, all other terms to the right

6x=8

x=8/6

x=1+1/3

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