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6(2x-1)=3(5-x)
We move all terms to the left:
6(2x-1)-(3(5-x))=0
We add all the numbers together, and all the variables
6(2x-1)-(3(-1x+5))=0
We multiply parentheses
12x-(3(-1x+5))-6=0
We calculate terms in parentheses: -(3(-1x+5)), so:We get rid of parentheses
3(-1x+5)
We multiply parentheses
-3x+15
Back to the equation:
-(-3x+15)
12x+3x-15-6=0
We add all the numbers together, and all the variables
15x-21=0
We move all terms containing x to the left, all other terms to the right
15x=21
x=21/15
x=1+2/5
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