6(2x-10)=3(4x-20)

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Solution for 6(2x-10)=3(4x-20) equation: 



6(2x-10)=3(4x-20)

We move all terms to the left:

6(2x-10)-(3(4x-20))=0

We multiply parentheses

12x-(3(4x-20))-60=0



We calculate terms in parentheses: -(3(4x-20)), so:

3(4x-20)

We multiply parentheses

12x-60

Back to the equation:

-(12x-60)



We get rid of parentheses

12x-12x+60-60=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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