6(2x-3)+33=3(4x+5)

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Solution for 6(2x-3)+33=3(4x+5) equation: 



6(2x-3)+33=3(4x+5)

We move all terms to the left:

6(2x-3)+33-(3(4x+5))=0

We multiply parentheses

12x-(3(4x+5))-18+33=0



We calculate terms in parentheses: -(3(4x+5)), so:

3(4x+5)

We multiply parentheses

12x+15

Back to the equation:

-(12x+15)



We add all the numbers together, and all the variables

12x-(12x+15)+15=0

We get rid of parentheses

12x-12x-15+15=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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