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6(2x-3)+3=3(3x+4)
We move all terms to the left:
6(2x-3)+3-(3(3x+4))=0
We multiply parentheses
12x-(3(3x+4))-18+3=0
We calculate terms in parentheses: -(3(3x+4)), so:We add all the numbers together, and all the variables
3(3x+4)
We multiply parentheses
9x+12
Back to the equation:
-(9x+12)
12x-(9x+12)-15=0
We get rid of parentheses
12x-9x-12-15=0
We add all the numbers together, and all the variables
3x-27=0
We move all terms containing x to the left, all other terms to the right
3x=27
x=27/3
x=9
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