6(2x-3)+4=3(3x-9)+64

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Solution for 6(2x-3)+4=3(3x-9)+64 equation: 



6(2x-3)+4=3(3x-9)+64

We move all terms to the left:

6(2x-3)+4-(3(3x-9)+64)=0

We multiply parentheses

12x-(3(3x-9)+64)-18+4=0



We calculate terms in parentheses: -(3(3x-9)+64), so:

3(3x-9)+64

We multiply parentheses

9x-27+64

We add all the numbers together, and all the variables

9x+37

Back to the equation:

-(9x+37)



We add all the numbers together, and all the variables

12x-(9x+37)-14=0

We get rid of parentheses

12x-9x-37-14=0

We add all the numbers together, and all the variables

3x-51=0

We move all terms containing x to the left, all other terms to the right

3x=51

x=51/3

x=17

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