6(2x-3)+4=3(3x-9)+64

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Solution for 6(2x-3)+4=3(3x-9)+64 equation:



6(2x-3)+4=3(3x-9)+64
We move all terms to the left:
6(2x-3)+4-(3(3x-9)+64)=0
We multiply parentheses
12x-(3(3x-9)+64)-18+4=0
We calculate terms in parentheses: -(3(3x-9)+64), so:
3(3x-9)+64
We multiply parentheses
9x-27+64
We add all the numbers together, and all the variables
9x+37
Back to the equation:
-(9x+37)
We add all the numbers together, and all the variables
12x-(9x+37)-14=0
We get rid of parentheses
12x-9x-37-14=0
We add all the numbers together, and all the variables
3x-51=0
We move all terms containing x to the left, all other terms to the right
3x=51
x=51/3
x=17

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