6(2x-3)+4=3(3x-9)+65

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Solution for 6(2x-3)+4=3(3x-9)+65 equation: 



6(2x-3)+4=3(3x-9)+65

We move all terms to the left:

6(2x-3)+4-(3(3x-9)+65)=0

We multiply parentheses

12x-(3(3x-9)+65)-18+4=0



We calculate terms in parentheses: -(3(3x-9)+65), so:

3(3x-9)+65

We multiply parentheses

9x-27+65

We add all the numbers together, and all the variables

9x+38

Back to the equation:

-(9x+38)



We add all the numbers together, and all the variables

12x-(9x+38)-14=0

We get rid of parentheses

12x-9x-38-14=0

We add all the numbers together, and all the variables

3x-52=0

We move all terms containing x to the left, all other terms to the right

3x=52

x=52/3

x=17+1/3

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