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6(2x-3)-(3x+1)=8
We move all terms to the left:
6(2x-3)-(3x+1)-(8)=0
We multiply parentheses
12x-(3x+1)-18-8=0
We get rid of parentheses
12x-3x-1-18-8=0
We add all the numbers together, and all the variables
9x-27=0
We move all terms containing x to the left, all other terms to the right
9x=27
x=27/9
x=3
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