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6(2x-3)=10x-2(-x+9)
We move all terms to the left:
6(2x-3)-(10x-2(-x+9))=0
We add all the numbers together, and all the variables
6(2x-3)-(10x-2(-1x+9))=0
We multiply parentheses
12x-(10x-2(-1x+9))-18=0
We calculate terms in parentheses: -(10x-2(-1x+9)), so:We get rid of parentheses
10x-2(-1x+9)
We multiply parentheses
10x+2x-18
We add all the numbers together, and all the variables
12x-18
Back to the equation:
-(12x-18)
12x-12x+18-18=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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