6(2x-3)=2(2x+1)

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Solution for 6(2x-3)=2(2x+1) equation:



6(2x-3)=2(2x+1)
We move all terms to the left:
6(2x-3)-(2(2x+1))=0
We multiply parentheses
12x-(2(2x+1))-18=0
We calculate terms in parentheses: -(2(2x+1)), so:
2(2x+1)
We multiply parentheses
4x+2
Back to the equation:
-(4x+2)
We get rid of parentheses
12x-4x-2-18=0
We add all the numbers together, and all the variables
8x-20=0
We move all terms containing x to the left, all other terms to the right
8x=20
x=20/8
x=2+1/2

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