6(2x-3)=2(2x+1)

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Solution for 6(2x-3)=2(2x+1) equation: 



6(2x-3)=2(2x+1)

We move all terms to the left:

6(2x-3)-(2(2x+1))=0

We multiply parentheses

12x-(2(2x+1))-18=0



We calculate terms in parentheses: -(2(2x+1)), so:

2(2x+1)

We multiply parentheses

4x+2

Back to the equation:

-(4x+2)



We get rid of parentheses

12x-4x-2-18=0

We add all the numbers together, and all the variables

8x-20=0

We move all terms containing x to the left, all other terms to the right

8x=20

x=20/8

x=2+1/2

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