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6(2x-3)=4(x-4)
We move all terms to the left:
6(2x-3)-(4(x-4))=0
We multiply parentheses
12x-(4(x-4))-18=0
We calculate terms in parentheses: -(4(x-4)), so:We get rid of parentheses
4(x-4)
We multiply parentheses
4x-16
Back to the equation:
-(4x-16)
12x-4x+16-18=0
We add all the numbers together, and all the variables
8x-2=0
We move all terms containing x to the left, all other terms to the right
8x=2
x=2/8
x=1/4
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