6(2x-3)=72+8x

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Solution for 6(2x-3)=72+8x equation: 



6(2x-3)=72+8x

We move all terms to the left:

6(2x-3)-(72+8x)=0

We add all the numbers together, and all the variables

6(2x-3)-(8x+72)=0

We multiply parentheses

12x-(8x+72)-18=0

We get rid of parentheses

12x-8x-72-18=0

We add all the numbers together, and all the variables

4x-90=0

We move all terms containing x to the left, all other terms to the right

4x=90

x=90/4

x=22+1/2

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