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6(2x-4)(4x-7)=0
We multiply parentheses ..
6(+8x^2-14x-16x+28)=0
We multiply parentheses
48x^2-84x-96x+168=0
We add all the numbers together, and all the variables
48x^2-180x+168=0
a = 48; b = -180; c = +168;
Δ = b2-4ac
Δ = -1802-4·48·168
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180)-12}{2*48}=\frac{168}{96} =1+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180)+12}{2*48}=\frac{192}{96} =2 $
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