6(2x-4)+2x=3(x-4)

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Solution for 6(2x-4)+2x=3(x-4) equation: 



6(2x-4)+2x=3(x-4)

We move all terms to the left:

6(2x-4)+2x-(3(x-4))=0

We add all the numbers together, and all the variables

2x+6(2x-4)-(3(x-4))=0

We multiply parentheses

2x+12x-(3(x-4))-24=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

14x-(3x-12)-24=0

We get rid of parentheses

14x-3x+12-24=0

We add all the numbers together, and all the variables

11x-12=0

We move all terms containing x to the left, all other terms to the right

11x=12

x=12/11

x=1+1/11

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