6(2x-4)=4(3-x)

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Solution for 6(2x-4)=4(3-x) equation: 



6(2x-4)=4(3-x)

We move all terms to the left:

6(2x-4)-(4(3-x))=0

We add all the numbers together, and all the variables

6(2x-4)-(4(-1x+3))=0

We multiply parentheses

12x-(4(-1x+3))-24=0



We calculate terms in parentheses: -(4(-1x+3)), so:

4(-1x+3)

We multiply parentheses

-4x+12

Back to the equation:

-(-4x+12)



We get rid of parentheses

12x+4x-12-24=0

We add all the numbers together, and all the variables

16x-36=0

We move all terms containing x to the left, all other terms to the right

16x=36

x=36/16

x=2+1/4

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