6(2x-5)+2=3(x-4)

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Solution for 6(2x-5)+2=3(x-4) equation: 



6(2x-5)+2=3(x-4)

We move all terms to the left:

6(2x-5)+2-(3(x-4))=0

We multiply parentheses

12x-(3(x-4))-30+2=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

12x-(3x-12)-28=0

We get rid of parentheses

12x-3x+12-28=0

We add all the numbers together, and all the variables

9x-16=0

We move all terms containing x to the left, all other terms to the right

9x=16

x=16/9

x=1+7/9

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