6(2x-5)+4x=78

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Solution for 6(2x-5)+4x=78 equation: 



6(2x-5)+4x=78

We move all terms to the left:

6(2x-5)+4x-(78)=0

We add all the numbers together, and all the variables

4x+6(2x-5)-78=0

We multiply parentheses

4x+12x-30-78=0

We add all the numbers together, and all the variables

16x-108=0

We move all terms containing x to the left, all other terms to the right

16x=108

x=108/16

x=6+3/4

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