6(2x-5)-3(x+1)-18x=

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Solution for 6(2x-5)-3(x+1)-18x= equation: 



6(2x-5)-3(x+1)-18x=

We move all terms to the left:

6(2x-5)-3(x+1)-18x-()=0

We add all the numbers together, and all the variables

-18x+6(2x-5)-3(x+1)=0

We multiply parentheses

-18x+12x-3x-30-3=0

We add all the numbers together, and all the variables

-9x-33=0

We move all terms containing x to the left, all other terms to the right

-9x=33

x=33/-9

x=-3+2/3

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