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6(2x-5)=(x+3)
We move all terms to the left:
6(2x-5)-((x+3))=0
We multiply parentheses
12x-((x+3))-30=0
We calculate terms in parentheses: -((x+3)), so:We get rid of parentheses
(x+3)
We get rid of parentheses
x+3
Back to the equation:
-(x+3)
12x-x-3-30=0
We add all the numbers together, and all the variables
11x-33=0
We move all terms containing x to the left, all other terms to the right
11x=33
x=33/11
x=3
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