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6(2x-5)=5x+19
We move all terms to the left:
6(2x-5)-(5x+19)=0
We multiply parentheses
12x-(5x+19)-30=0
We get rid of parentheses
12x-5x-19-30=0
We add all the numbers together, and all the variables
7x-49=0
We move all terms containing x to the left, all other terms to the right
7x=49
x=49/7
x=7
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