6(2x-7)+4x=3(3x-4)+30

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Solution for 6(2x-7)+4x=3(3x-4)+30 equation:



6(2x-7)+4x=3(3x-4)+30
We move all terms to the left:
6(2x-7)+4x-(3(3x-4)+30)=0
We add all the numbers together, and all the variables
4x+6(2x-7)-(3(3x-4)+30)=0
We multiply parentheses
4x+12x-(3(3x-4)+30)-42=0
We calculate terms in parentheses: -(3(3x-4)+30), so:
3(3x-4)+30
We multiply parentheses
9x-12+30
We add all the numbers together, and all the variables
9x+18
Back to the equation:
-(9x+18)
We add all the numbers together, and all the variables
16x-(9x+18)-42=0
We get rid of parentheses
16x-9x-18-42=0
We add all the numbers together, and all the variables
7x-60=0
We move all terms containing x to the left, all other terms to the right
7x=60
x=60/7
x=8+4/7

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