6(2x-7)-3=6(x-2)+9

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Solution for 6(2x-7)-3=6(x-2)+9 equation: 



6(2x-7)-3=6(x-2)+9

We move all terms to the left:

6(2x-7)-3-(6(x-2)+9)=0

We multiply parentheses

12x-(6(x-2)+9)-42-3=0



We calculate terms in parentheses: -(6(x-2)+9), so:

6(x-2)+9

We multiply parentheses

6x-12+9

We add all the numbers together, and all the variables

6x-3

Back to the equation:

-(6x-3)



We add all the numbers together, and all the variables

12x-(6x-3)-45=0

We get rid of parentheses

12x-6x+3-45=0

We add all the numbers together, and all the variables

6x-42=0

We move all terms containing x to the left, all other terms to the right

6x=42

x=42/6

x=7

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