6(2x-8)-3=6(x-7)+(3)

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Solution for 6(2x-8)-3=6(x-7)+(3) equation: 



6(2x-8)-3=6(x-7)+(3)

We move all terms to the left:

6(2x-8)-3-(6(x-7)+(3))=0

We multiply parentheses

12x-(6(x-7)+3)-48-3=0



We calculate terms in parentheses: -(6(x-7)+3), so:

6(x-7)+3

We multiply parentheses

6x-42+3

We add all the numbers together, and all the variables

6x-39

Back to the equation:

-(6x-39)



We add all the numbers together, and all the variables

12x-(6x-39)-51=0

We get rid of parentheses

12x-6x+39-51=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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