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6(2x-8)-5=6(x-4)+7
We move all terms to the left:
6(2x-8)-5-(6(x-4)+7)=0
We multiply parentheses
12x-(6(x-4)+7)-48-5=0
We calculate terms in parentheses: -(6(x-4)+7), so:We add all the numbers together, and all the variables
6(x-4)+7
We multiply parentheses
6x-24+7
We add all the numbers together, and all the variables
6x-17
Back to the equation:
-(6x-17)
12x-(6x-17)-53=0
We get rid of parentheses
12x-6x+17-53=0
We add all the numbers together, and all the variables
6x-36=0
We move all terms containing x to the left, all other terms to the right
6x=36
x=36/6
x=6
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